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9x^2-520x+1936=0
a = 9; b = -520; c = +1936;
Δ = b2-4ac
Δ = -5202-4·9·1936
Δ = 200704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{200704}=448$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-520)-448}{2*9}=\frac{72}{18} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-520)+448}{2*9}=\frac{968}{18} =53+7/9 $
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